PrashanthP Posted May 23 Report Share Posted May 23 Hello. I wanted to create a byte addressable memory in IPXACT with below code Here width tells the number of bits per location. If width is 8 then is it byte addressable ? And the total number of address locations are 2**10 (1024 locations starting from base address 0) ? and what is the difference between addressable units and addressunitbits ? Quote Link to comment Share on other sites More sharing options...
kock Posted May 23 Report Share Posted May 23 Hi Prashanth, If you want a byte addressable memory then the addressUnitBits value shall be 8 (which is the default value). The number represents number of data bits in each address increment. Hence, the addressable unit is then a byte. The range describes the number of addressable units. The width describes the number of data bits that can be accessed in a single transaction. Best regards, Erwin Quote Link to comment Share on other sites More sharing options...
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