ashwathgan Posted September 22, 2015 Report Share Posted September 22, 2015 Hi all I have a SystemC thread. I create two instances of this thread in main ( so, now two threads are ready to run) What I tired was to randomize the execution order of these two threads, hence i used a event.notify() But when I do that, i get the warning "immediate Self Notification ignored" Where am I going wrong? thanks in advance regards Ashwath Quote Link to comment Share on other sites More sharing options...
ralph.goergen Posted September 22, 2015 Report Share Posted September 22, 2015 Hi. event.notify() is so-called immediate notification. I.e., the event is notified in the same (current) delta cycle. When you use this kind of notification in a process that is sensitive to that event, this usually makes no sense. The state of signals cannot change during one dalta cycle. Hence, this will (or might) lead to endless executions of this process without reaching the next delta at any time. Greetings Ralph Quote Link to comment Share on other sites More sharing options...
ashwathgan Posted September 23, 2015 Author Report Share Posted September 23, 2015 Thank you Ralph. I understand. But i want to achieve something like the following I have thread A which can start immediately after start of simulation(sc_start()) and it takes 5 time period to complete I have thread B which can also start immediately after start of simulation and takes 5 time period Though A and B can potentialy start and run at the same time, i wanted to achieve a random interleaving of both these threads . For example, thread A must start at 0 and run till 5 through wait(time_period,SC_NS) and again runs till 10ns. Till now b must be blocked, so now B blocks A and runs for number of times and A starts back again Regards Ashwath Quote Link to comment Share on other sites More sharing options...
ralph.goergen Posted September 23, 2015 Report Share Posted September 23, 2015 Hi. 'Unfortunately', there is no randomness in the execution order of processes within the same delta cycle. http://forums.accellera.org/topic/5052-accellera-kernel-process-order/#entry12122 When the two threads start at the same time and have the same period, they will run always in the same order. This is part of the SystemC implementation and cannot be changed without changing the SystemC kernel. There are some approaches about this, patches for the SystemC kernel to add randomness in the execution order, but I do not know the current status of them. E.g.: http://www.teisa.unican.es/HetSC/downloads/SC_kernel_Improvements/uc_rand_sched/Patch_Kernel_sc_pseudorandom_sched_Eng.pdf If you do not communicate via signal and you do not have dependencies on the delta cycle, you can move the execution of the threads to the next delta cycle by adding a 'wait(SC_ZERO_TIME)' and execute in random cases. Greetings Ralph PARVINDER PAL SINGH 1 Quote Link to comment Share on other sites More sharing options...
ashwathgan Posted September 24, 2015 Author Report Share Posted September 24, 2015 Thanks a lot Ralph The information was very useful Quote Link to comment Share on other sites More sharing options...
dakupoto Posted September 27, 2015 Report Share Posted September 27, 2015 Thank you Ralph. I understand. But i want to achieve something like the following I have thread A which can start immediately after start of simulation(sc_start()) and it takes 5 time period to complete I have thread B which can also start immediately after start of simulation and takes 5 time period Though A and B can potentialy start and run at the same time, i wanted to achieve a random interleaving of both these threads . For example, thread A must start at 0 and run till 5 through wait(time_period,SC_NS) and again runs till 10ns. Till now b must be blocked, so now B blocks A and runs for number of times and A starts back again Regards Ashwath Hello Sir, Thread scheduling is controlled by the underlying operating system and the application programmer has no control on the activities of the thread scheduler. So which of two threads A or B will be invoked at start cannot be predicted. Threads use shared memory, and only the operating system has the privileges to control memory allocation/deallocation. Hope that helps. Quote Link to comment Share on other sites More sharing options...
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