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xor operation


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I have to perform xor operation between two following numbers 



unsigned int a;

unsigned int b;



a xor_reduce b;


Why do you call the operation "xor reduce"?  A bitwise "xor" operation has the same number of bits as its operands.
Have you tried the (C++) operator "xor"?

unsigned int a = 42;
unsigned int b = 21;
unsigned int c = (a xor ; // or in short notation (a ^ 

An "xor reduce" operation as provided by the SystemC datatypes would be defined on a single operand and return a single bit after applying the "xor" bit by bit.  This is not defined for the built-in C++ datatypes.


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