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Suhyun

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  1. Hi Erwin, Thanks for your answer. Your answer is very helpful to me. I modified register description based on your answer. (addressUnitBits 8 -> 16) Q1)Is the description below right? [ip-xact information] - slave interface. bitInLau : 8 - addressblock width : 16 - addressUnitBits : 8 -> 16 - register name A_0: - register offset : 0 - register size : 16 - register name A_1: - register offset : 1 - register size : 16 - register name B_0: - register offset : 2 - register size : 16 - register name
  2. The above descriptoin have probelm about SCR7.5... (The size of any register shall be no greater than the width of the containing address block.) [ip-xact information] - slave interface. bitInLau : 8 - addressblock width : 16 - addressUnitBits : 8 - register name A_0: - register offset : 0 - register size : 16 - register name A_1: - register offset : 1 - register size : 16 - register name B_0: - register offset : 2 - register size : 16 - register name B_1: - register offset : 3 - register size : 16 addr_offset@ip-
  3. Hi, I have some question about access the register below case... [ip-xact information] - slave interface. bitInLau : 8 - addressblock width : 16 - addressUnitBits : 8 - register name A: - register offset : 0 - register size : 32 - register name B: - register offset : 1 - register size : 32 Q1) Does the above description have any problem in the ip-xact standard? Q2) In case of the above description, maximum single transfer size is 16. Because address block width is 16. Is it right? Q3) I know as below. Is it right? a
  4. Hi, I wanted to know calculating the bus address. [information of register in IP-XACT] - base address : 0x40000 - address offset : 1 - address unit bits : 32 - salve.bitsInLau : 8 memory_map_bit_address = bit_number_in_address_block + addressBlock.baseAddress x memoryMap.addressUnitBits = (1 + 0x40000) * 32 = (1 + 262,144)*32 = 8,388,640 slave_bus_address = memory_map_bit_address / slave.bitsInLau
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